2x^2+10x-48/8x+64

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Solution for 2x^2+10x-48/8x+64 equation: 


x in (-oo:+oo)

2*x^2+10*x-((48/8)*x)+64 = 0

2*x^2+10*x-6*x+64 = 0

2*x^2+4*x+64 = 0

DELTA = 4^2-(2*4*64)

DELTA = -496

DELTA < 0

x belongs to the empty set

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